enter expression, e.g. 2+2
supported extra functions:
supported extra functions:
- C(n,r) binomial function (also notated as nCr, eg. C(6,3) = 6C3 = 20)
- h(x,n,a,N) hypergeometric distribution, eg. with a pair hit a set on flop h(1,3,2,50) = 0.115
- hs(x_{1},x_{2},n,a,N) cumulative version, eg. with pair hit set or quads on flop hs(1,2,3,2,50) = 0.118
> Fill in
At least hitting a pair, two pair, triple or fullhouse.
Lets say you get the following cards A and J
Click Fill in and you get the probability ~0.49
About 50% chance
At least hitting a pair, two pair, triple or fullhouse.
Lets say you get the following cards A and J
x_{1} = 1 | You need at least 1 of the outs to get a pair |
x_{2} = 2 | You dont mind getting more than one pair, (you still get minimum a pair). To include those odds you set x_{2} = n. If you only want a pair in total, then you set x_{2} to same as x_{1} |
n = 5 | There are 5 cards to come from the preflop state |
a = 6 | There are three A and three J left in the deck, you have 6 outs |
N = 50 | You have received two cards, then the deck size is now 50 |
About 50% chance
> Fill in
Lets say you get the following cards T and 3
You only want 3 hearts on the board.
Click Fill in and you get the probability ~0.058
About 6% chance
Lets say you get the following cards T and 3
You only want 3 hearts on the board.
x_{1} = 3 | You need at least 3 of the outs to get a flush |
x_{2} = 3 | You want to hit maximum 3 flush cards |
n = 5 | There are 5 cards to come from the preflop state |
a = 11 | Since you got two of the suited, there are 11 left in the deck |
N = 50 | You have received two cards, then the deck size is now 50 |
About 6% chance
> Fill in
Lets say you are 4 players for the flop and you get the following cards Q and Q
Click Fill in and you get the probability ~0.24
About 24% chance of at least one 5 is out there
Lets say you are 4 players for the flop and you get the following cards Q and Q
You know nothing about the players, the flop comes 5 5 9
x_{1} = 1 | The players need at least 1 of the outs |
x_{2} = 2 | Any player could have 1 or 2 of those 5's |
n = 6 | There are 6 cards to be given to the 3 other players |
a = 2 | Since two 5's are on the board, there are 2 left in the deck |
N = 47 | You have received two cards, and 3 cards on the flop, the deck size is now 47 |
About 24% chance of at least one 5 is out there
> Fill in
Lets say you get the following cards J and T
Click Fill in and you get the probability ~0.04
About 4% chance
Lets say you get the following cards J and T
The flop comes 2 9 A
This is solved by Combinations without repetition: |
You need at least 2 of the outs to get a straight, the runner cards for straight are 7,8 or 8,Q or Q,K |
You take all the possibilites outcome for the running straight and divide by all the possible combinations for the next 2 cards. The calculations is (7,8 combo or 8,Q combo or Q,k combo) divided by all possible combos for next 2 cards. |
Possible combinations for 7,8 combo is C(4,1) * C(4,1) = 24, picking 1 out of 4 is C(4,1) Possible combinations for 8,Q combo is C(4,1) * C(4,1) = 24 Possible combinations for Q,K combo is C(4,1) * C(4,1) = 24 |
You have the 2 cards, the flops has 3, then there's 47 cards left in the deck. Combinations of picking 2 out of 47 is calculated by the function C(n,r). C(47,2) = 1081 |
(C(4,1)*C(4,1) + C(4,1)*C(4,1) + C(4,1)*C(4,1)) / C(47,2) = (24 + 24 + 24) / 1081 |
About 4% chance
> Fill in
Lets say you get the following cards J and T
Click Fill in and you get the probability ~0.04
About 4% chance
Lets say you get the following cards J and T
The flop comes 2 9 A
x_{1} = 2 | You need to hit minimum 2 flush cards |
x_{2} = 2 | You can hit maximum 2 flush cards |
n = 2 | There are 2 cards to come after the flop |
a = 10 | The flop has the 2 flush cards, you have 1, then the're 10 flush cards left |
N = 47 | You have received two cards, and 3 cards on the flop, the deck size is now 47 |
About 4% chance
> Fill in
Lets say you get the following cards T and T
Click Fill in and you get the probability ~0.305
About 31% chance
Notice, though, that those probabilities would be lower
if we consider that at least one opponent happens to hold one of those overcards.
Lets say you get the following cards T and T
x_{1} = 0 | 0 overcard to hit |
x_{2} = 0 | maximum 0 overcards on the flop |
n = 3 | There are 3 cards to come for the flop |
a = 16 | There are four Aces, four Kings, four Queens and four Jacks in the deck, that's 16 outs. |
N = 50 | You have received two cards, then the deck size is now 50 |
About 31% chance
Notice, though, that those probabilities would be lower
if we consider that at least one opponent happens to hold one of those overcards.
> Fill in
Lets say you get the following cards A and Q
Click Fill in and you get the probability ~0.24
About 24% chance
Lets say you get the following cards A and Q
The flop comes 2 7 J
This is solved by the formula: 1 - ((47 - outs) / 47 ) * ((46 - outs) / 46 ) Where outs is a value between 1 and 21. |
You have 6 outs to get a pair (3 aces and 3 queens) outs = 6; 1 - ((47 - outs) / 47 ) * ((46 - outs) / 46 ) |
Nb. for the turn only the formula is: 1 - ((47 - outs) / 47 ) Nb. for the river only the formula is: 1 - ((46 - outs) / 46 ) |
About 24% chance
> Fill in
Lets say you get the following cards T and T
Click Fill in and you get the probability ~0.305
About 31% chance
Notice, though, that those probabilities would be lower
if we consider that at least one opponent happens to hold one of those overcards.
Lets say you get the following cards T and T
This is solved by the formula: C( 4 * x - 6 , 3 ) / C( 50 , 3 ) Where x is a value between 3 and 13. |
e.g. if you have pocket 3 the value x is 3 e.g. if you have pocket tens the value x is 10 e.g. if you have pocket kings the value x is 13 |
You have pocket tens, then you set x = 10 x = 10; C( 4 * x - 6 , 3 ) / C( 50 , 3 ) |
About 31% chance
Notice, though, that those probabilities would be lower
if we consider that at least one opponent happens to hold one of those overcards.
> Fill in
Lets say there are 36 numbers, and there are 6 winner numbers. You have to hit atleast 3 correct out of 6.
Click Fill in and you get the probability ~0.0451.
About 4.51% chance
Lets say there are 36 numbers, and there are 6 winner numbers. You have to hit atleast 3 correct out of 6.
x_{1} = 3 | minimum |
x_{2} = 6 | maximum |
n = 6 | There are 6 numbers to be drawed |
a = 6 | There are 6 correct numbers |
N = 36 | There are 36 possible numbers |
About 4.51% chance
AA | AKo | AQo | AJo | ATo | A9o | A8o | A7o | A6o | A5o | A4o | A3o | A2o |
AKs | KK | KQo | KJo | KTo | K9o | K8o | K7o | K6o | K5o | K4o | K3o | K2o |
AQs | KQs | QJo | QTo | Q9o | Q8o | Q7o | Q6o | Q5o | Q4o | Q3o | Q2o | |
AJs | KJs | QJs | JJ | JTo | J9o | J8o | J7o | J6o | J5o | J4o | J3o | J2o |
ATs | KTs | QTs | JTs | TT | T9o | T8o | T7o | T6o | T5o | T4o | T3o | T2o |
A9s | K9s | Q9s | J9s | T9s | 99 | 98o | 97o | 96o | 95o | 94o | 93o | 92o |
A8s | K8s | Q8s | J8s | T8s | 98s | 88 | 87o | 86o | 85o | 84o | 83o | 82o |
A7s | K7s | Q7s | J7s | T7s | 97s | 87s | 77 | 76o | 75o | 74o | 73o | 72o |
A6s | K6s | Q6s | J6s | T6s | 96s | 86s | 76s | 66 | 65o | 64o | 63o | 62o |
A5s | K5s | Q5s | J5s | T5s | 95s | 85s | 75s | 65s | 55 | 54o | 53o | 52o |
A4s | K4s | Q4s | J4s | T4s | 94s | 84s | 74s | 64s | 54s | 44 | 43o | 42o |
A3s | K3s | Q3s | J3s | T3s | 93s | 83s | 73s | 63s | 53s | 43s | 33 | 32o |
A2s | K2s | Q2s | J2s | T2s | 92s | 82s | 72s | 62s | 52s | 42s | 32s | 22 |